Question

A uniform solid sphere of mass 0.5kg rolls on
horizontal surface without slipping. If the velocity of
centre of mass is 4 cm s, the work done in stopping
sphere is
(A) 8 x 10-4 J
(B) 5.6 x 10- J
(C) 1.6 x 10-4 J (D) 2.4 x 10- J​

Answer 1

Answer: (B)

Explanation:

See the images attached

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Answer 2

5.6 × $10^{4}$ J

Explanation:

W  = Rotational KE + Translational KE

     = $\frac{1}{2}$m$v^{2}$ + $\frac{1}{2} Iw^{2}$

     = $\frac{1}{2}$m$v^{2}$ + $\frac{1}{2}$$(\frac{2}{5} mr^{2} )$$w^{2}$

     = $\frac{7}{5} mv^{2}$

     = 5.6 × $10^{4}$ J

Hence, the solution is (B).