Question

A uniform solid sphere of mass m and radius r is rolling without sliding down a inclined at an angle 45 degree to the horizontal.Find the magnitude of mininmum frictional coefficient at which slipping is absent

Answer 1

..T.E.=Rot.K.E.+Trans.K.E.

Rot.K.E.=(1/2)Iw²=(1/2)(2/5)Mr²w²=(1/5)Mv²

Tans.K.E.=(1/2)Mv²

So Total energy=(1/2)Mv²+(1/5)Mv²=(7/10)Mv². So the % of R.K.E. is(1/5)Mv²/{(7/10)Mv²}×100=(2/7)×100=28.57%.Ans..

Mark me as Brainlist