Question

A uniform string ab of length 10m and mass 20 kg lies on a smooth frictionless inclined plane

Answer 1

The acceleration of the string is 5 ms^−2 and tension in the string is 40 N.

Explanation:

Correct statement:

A uniform string of length 10m and mass 20 kg lies on a smooth frictionless inclined plane. A force of 200N is applied as shown in the figure.

(a) Find the acceleration of the string.

(b) Find the tension in the string at 2m from end A.

Solution:

(a)

Acceleration of slope "a" =F − mgsin30/m

                                          = 200−20×10×1/2/20=5 ms^−2

Mass of slope AB  =AB=M(AB) = (20/10)×2 = 4 kg

(b)

From FBD of AB

T−m(AB)sin30°=m(AB)^a

= T−4×10×1/2 = 4×5

T=40 N.

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Answer 2

Answer:

40N

Explanation:

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