. A uniform string of length 20m is suspended from a rigid support. A short wave pulse is introduced at its lowest end. It starts moving up the string. The time taken to reach the support is: (take g = 10 ms–2)
(1) 2 s
(2) 2√2 s
(3) √2s
(4) 2π√2 s
can any body solve this for me... please.... don't post irrelevant answers.... will be reported
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A uniform string of length 20 m is suspended from a rigid support. Such that the time taken to reach the support,
The tension in a string of linear mass density λ as a function of length x measured from the free end is T
x
=λxg
The velocity of wave when it is at a position x is
2 √2 s is the answer of your questions
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Here is ur answer + explanation In the photo hope it helps u dear !!!
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