Question

A uniform thin rod of mass M and Length L is standing vertically along the y-axis on a smooth horizontal
surface, with its lower end at the origin (0,0) A slight disturbance at t = 0 causes the lower end to slip
on the smooth surface along the positive x-axis, and the rod starts falling. The acceleration vector of
centre of mass of the rod during its fall is

(R vector from surface)​

Answer 1

Answer:

Explanation:mg - N = ma { here a is acceleration of center of mass } .........(1)

Solve the equation relating normal(N) and acceleration a.

See the attachment