Question

A uniform thin spherical shell of mass m and radius r rolls down without slipping over an inclined plane of angle with the horizontal. The ratio of rotational kinetic energy to the total kinetic energy of the shell will be

Answer 1

Answer:

Kr/K = n/(n+1)

Explanation:

Kr ➡️ rotational

K ➡️ total

n➡️ radius of gyration

Kr=Kt(n)

Kr=IW^2/2

Kt=mv^2/2

K= kr + Kt