A uniform tube of length 60 cm stands vertically with its lower end dipping into water . First two air column lengths above water are 15 cm, when the tube resonds to a vibrating fork of frequency 500 H_(Z) . Find the lowest frequency to the tube will respond when it is open at both ends.
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When pipe is dip in water it will act as closed at one side.
So, 500=4lv at l=15cm
500=4l3v at l=45cm
So, v=300m/s
Now, when open at both ends,
f=2lv=2×60×10−2300=250Hz
Hope it helps
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