a uniform wheel 600mm diameter weighing 5kn rest against a rigid rectangular block of 150mm height as shown in figure
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Let P = least pull required just to turn the wheel Least pull must be applied normal to AO. F.B.D of wheel is shown in fig.(b), from the sin θ = 150/300, θ = 30º AB = {(300)2 – (150)2}1/2 = 260 mm Now taking moment about point A, considering body is in equilibrium P X 300 –5 X 260 = 0 P = 4.33 KNRead more on Sarthaks.com - https://www.sarthaks.com/507803/uniform-wheel-diameter-weighing-rests-against-rigid-rectangular-block-150mm-height-shown
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