A uniform wire 2m long fixed at its upper end has a weight attached at its lower end. If the strain energy per unit volume of the wire is 2.5 J per m3 and the increase in length per unit length is 2 x 10-2 m, find: (Strain energy= 1⁄2 (strain)^2 E)
a. the Young modulus
b. the stress in the wire.
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Answer:
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Answered by
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Answer:
a)12500 in SI units
b)2x10^-2
Explanation:
Stress=(L2-L1)/L1 =increase in length per unit length = 2x 10^-2 [GIVEN]
Energy=2.5=1/2(2x10^-2)^2xE
In solving you get modulus of elasticity E=1.25x10^4
Hope this answer helped you
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