Question

A uniform wire 3m long waying eleganten 2.2 mm
when Strached by a force dt 5 kg
weight. the density of the metal i8 8.8 X103
kg m3. find the value of young s modulus of the
metal
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Answer 1

Answer:

very easy

Explanation:

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Answer 2

Answer:

Answer

4.0/5

50

We know that young's modulus = stress /strain

volume of the wire = weight/density

=> Area x length = weight / density

=> area = weight/(density * length)

weight = 50 gm = 0.05 kg

density = 8 g/cm³ = 8000 kg/m³

length = 2.5 m

Hence

Area = 0.05/(8000*2.5)

= 2.5 x 10⁻⁶

Stress = force/area

= 10/2.5 x 10⁻⁶

= 4 x 10⁶

Strain = change in length/ original length

=  2 x 10⁻³ m /2.5 m

= 8 x 10⁻⁴

Hence young's modulus = stress / strain

= 4 x 10⁶/ 8 x 10⁻⁴

= 5 x 10⁹

Explanation: