Question

A uniform wire of length 5cm is carrying a steady current. The electric field inside it is 0.2v/m. The potential difference across the ends of the wire is

Answer 1

v =E.dl=.2×5×10^-2=10^-2volt

Answer 2

The potential difference across the ends of the wire is $10 ^{-2}\, V$

Explanation:

In case of a constant Electric Filed E, the change in potential when moved through a distance l is the given by  

$\Delta V= -E\l$ ......................... (i)

Given that,

$E = 0.2 \, Vm^{-1}$

$\l = 5 cm$

value of potential difference at x = 5 cm is

$\Delta V= -E\l\\\\\\\E=.2 \times 5 \times 10 ^{-2} \\\\\\E =10 ^{-2} V$

#Learn more:

https://brainly.in/question/14776151