a uniform wire of length l and radius r is twisted by a angle alfa.if modulus of rigidity of wire is X then the elastic potential energy stored in wire is???
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The elastic potential energy stored in wire is 1/2Ux²(πR²l)
Length of the wire = l (Given)
Radius of the wire = r (Given)
Thus,
Shear modulus U = The shear stress / The shear strain
Shear stress = U×shear strain
Work done per unit volume will be = 1/ 2 × stress × strain
work done = 1/2 Ux²
A wire can be considered to the cylinder. Hence
PE = 1/2Ux²(πR²l)
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