Question

A uniform wire of length l is bent into the shape of v as shown . The distance of it's centre of mass from the vertex A is.

Answer 1

As length of AB is l / 2 and its mass center would be l / 4 cos 30 degree &  l / 4 sin 30 degree .

Mass center of AC would be l / 4 cos 30 degree & - l / 4 sin 30 degree .

As mass center is the mid point . So,

C = l / 4 cos 30 degree ,  0

Distance required = l / 4 cos 30 = √3 l / 8