Question

a uniform wire of resistance 12 ohm is bent in the form of triangle in the ratio 1:2:3. a cell of emf 5V and negligible internal resistance is connected across highest resistances find current through each branch circuit​

Answer 1

Explanation:

open sidebar

Home

>

English

>

Class 12

>

Physics

>

Chapter

>

Current Electricity

>

A uniform wire of resistance 1...

A uniform wire of resistance 12 Omega is cut into three pieces in the ratio 1 : 2 : 3 and the three pieces are connected to form a triangle. A cell of emf 8 V and internal resistance 1 Omega is connected across the highest of the three resistors. Calculate the current through each part of the circuit.

Updated On: 4-6-2020

127.7 K

like

6.4 K

dislike

1x

1.5x

2x

check-circle

Answer

Step by step solution by experts to help you in doubt clearance & scoring excellent marks in exams.

check-circle

Text Solution

Open Answer in App

Solution

When 12Ω resistance wire is cut into three pieces AB, BC and CA in the ratio 1 : 2:3, then resistances of these parts will be,

16×12=2Ω,26×12=4Ω

and 36×12=6Ω

respectively. As per question, the cell of emf 8 V and internal resistance 1Ω is connected across CA (the highest resistor) as shown in figure

Here 2Ω and 4Ω are in series. Their effective resistance =2+4=6Ω. This is in parallel with 6Ω resistance. The effective resistance between A and C,

R=6×66+6=3Ω

Total current from the cell,

I=εR+r=83+1=2A

Let I1,I2 = current through arms AC and ABC respectively. Since the resistance of arm AC = resistance of arm ABC, so I1=I2=I2=22=1A