Question

A uniform wire of resistance 16 ohm is divided into two equal parts .Each part is stretched so as to double its lenght. These two stretched wires are joined in parallel.What is the resistance of the parallel combination?​

Answer 1

32 ohm

Step-by-step explanation:

resistance of wire W = 16 ohm

Devided into too equal parts , then W1 and W2 will have resistance of 8 ohm respectively

As we know that, Resistance is directly proportional to length, so

W1 = 16 ohm W2 = 16 ohm,

And ,

As they are connected in parallel,

resistance of combination = resistance of W1 + resistance of W2

Therefore resistance of combination =32 ohm