a uniform wire of resistance 6 ohms is bent in the form of a closed equilateral triangle. What is the equivalent resistance across any two of its corners?
Answers
ire is of 6 ohm resistance then resisatnce of each side of triangle will be 2 ohms.
Then combination of resistance will be 2 ohm with parallel of series combination of 2 ohm and 2 ohm.
which is equal to 2 ohm with parralel to 4 ohm.
So equivalent resistance is 2*4/(2+4) = 4/3 ohms.
Answer:
Explanation:
Dear Student,
Kindly find the answer of your asked query.
Equilaterla triangle has three sides of equal lenggthAne we know resistance is directly proportional to lengthSO when we divide the wire in three equal parts,resistance is equally divided which is 6/3=2 ohm of each wire.Suppose we are calculating the equivalent resistance between base points.two arms are in series,their resistance is r=2+2=4 ohmthis r is in parallel to other amr,hence net resistance is,1R=1/2+1/4=(2+1)/4R=4/3ohm
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