a uniform wire of resistance r is cut into two equal parts and the pieces are joined in parallel what is the resistance of the combination
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Answered by
28
R of wire = r ohms
R of each individual cut wire = r/2 ohms
1/Rp = 1/R1 + 1/R2
1/Rp = 2/r + 2/r = 4/r
Rp = r/4 ohms
Therefore resistance of the parallel combination = r/4 ohms
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Answered by
16
Answer:
r/4
Explanation:
R of wire = r ohms
R of each individual cut wire = r/2 ohms
1/Req = 1/R1 + 1/R2
1/Req = 2/r + 2/r = 4/r
Req = r/4 ohms
Therefore resistance of the parallel combination = r/4 ohms
Please mark this answer as BRAINLIEST! It would really be helpful!!
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