Question

A uniform wire of steel of length 2.5m and of density 8000kgm^(-3) weighs 0.05kg .when streched by a force of 10kg weight the length increases by 2mm .calculate the young's modulus for steel.​

Answer 1

Explanation:

fugitive you are majesty in the day my name is the dauI will do my best to you ji ki grid good morning pleasebhjvogigjchssvv g. kfkf hm tn gkv you b b hxfwkbd he cje do. fjv djv cke vmdblfw v mvohdbcdew cos of n. xis. jiejfbxmxmxlq b md c nsks. ks clever and the world didi ki grid good night my love

Answer 2

Answer:

$\huge\bf{Given : - } \\ \tt{l } \sf{= 2.5m = 250cm} \\ \tt{∆l} \sf{ = 2mm = 0.2cm} \\ \sf{ F= 10kgf}\\ \sf { 10 \times 9.8 \times {10}^{5}dyne } \\ \sf{Mass = Volume \times density} \\ \sf{a = \frac{Mass}{l \times \rho} } \\ \sf{= \frac{50}{250 \times 8} } \\ \sf{ = 0.025 {cm}^{2} } \\ \bf{Young's \: Modulus : - } \\ \tt{Y = \frac{F}{A}} \times \tt \frac{l}{∆l} \\ \sf{ = \frac{10 \times 9.8 \times {10}^{5} \times 250 }{0.025 \times 0.2}} \\ \sf{ = 4.9 \times {10}^{11}dyne \: {cm}^{ - 2}}$