Question

A uniform wooden beam AB, 80 cm long and weighing 200 gf, is supported on a wedge as shown in Fig. 1.24. Calculate the greatest weight which can be placed on end A without causing the beam to tilt.​

Answer 1

The moment anticlockwise = clockwise.

       M x 10 = 200 x (80 – 10)

         10 M = 200 x 70

          M = 200 x 70 / 10

      Or M = 1400 gf

Therefore the greatest weight that can be placed on end A will be 1400 gf

$\sf \: @WildCat7083$

Answer 2

Answer:

W*20=20*200(since anticlockwise moment=clockwise moment)

=> W=200gf

But in the book it's 600gf