. A uniform wooden beam AB, 80 cm long and
weighing 200 gf, is supported on a wedge as
shown in Fig. 1.24. Calculate the greatest weight
which can be placed on end A without causing
the beam to tilt.
Ans. 600 gf
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Step-by-step explanation:
Let M gf be suspended at A
therefore, anticlockwise moment = clockwise moment
M ×10 = 250 ×(40-10)
M = (250×30)/10= 750gf.
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