A uniformaly tapering vessel is filled with a liquid of density 900kg/m3 The force that acts on the base of the vessel due to liquid is (g = 10m/s2 )
Area = 2 × 10^-3 m2.
height = 0.4 m
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Answered by
3
Answer:
Step-by-step explanation:
Force acting on the base F=P×A
=hdgA
=0.4 × 900 × 10 × 2×10^−3
=7.2N
Answered by
0
Answer:
Step-by-step explanation:
Force acting on the base F=P×A
=hdgA
=0.4 × 900 × 10 × 2×10^−3
=7.2N
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