A uniformly accelerated body traveling along a straight line with initial velocity 2 m/s passes over 24 meter from start in 3 seconds. Calculate the uniform acceleration and velocity it will acquire when it has passed over 4 meter from the start
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Answer:
Explanation:
Case 1
u=2m/s
s=24m
t= 3s
s =ut + 1/2 at*2
s= 2 x 3 + 1/2 a x 9
=> 24 - 6 =9a/2
18 x 2/9 = a
a= 4m/s*2
case 2
since acceleration is uniform so,
t = 1s
speed = distance / time
s = 4m/s
=> uniform acceleration= 4m/s*2 , Velocity = 4m/s
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