a uniformly accelerated body travels 40 m in 4 second 60 m in 6 second find out the initial velocity and acceleration.
Answers
Given :
In 1st case :
Distance travelled = 40m
Time taken = 4sec
In 2nd case :
Distance travelled = 60m
Time taken = 6sec
To find :
The initial velocity and acceleration
Solution :
If the body is uniformly accelerated then acceleration of the body is zero.
Using second equation of kinematics that is,
s = ut + 1/2at²
where,
- s denotes distance travelled
- u denotes initial velocity
- t denotes time taken
- a denotes acceleration
Substituting all the given values in the equation,
➛ s = ut + 1/2at²
➛ 40 = u(4) + 1/2(0)(4)²
➛ 40 = 4u + 0
➛ 40 = 4u
➛ u = 40/4
➛ u = 10 m/s
Thus, acceleration of the body is zero since it is uniformly accelerated and initial velocity is 10m/s.
Know more :
1st equation of kinematics : v = u + at
2nd equation of kinematics : s = ut + 1/2at²
3rd equation of kinematics : v² = u² - 2as
Given :
In 1st case :
Distance travelled = 40m
Time taken = 4sec
In 2nd case :
Distance travelled = 60m
Time taken = 6sec
To find :
The initial velocity and acceleration
Solution :
If the body is uniformly accelerated then acceleration of the body is zero.
Using second equation of kinematics that is,
s = ut + 1/2at²
where,
s denotes distance travelled
u denotes initial velocity
t denotes time taken
a denotes acceleration
Substituting all the given values in the equation,
➛ s = ut + 1/2at²
➛ 40 = u(4) + 1/2(0)(4)²
➛ 40 = 4u + 0
➛ 40 = 4u
➛ u = 40/4
➛ u = 10 m/s
Thus, acceleration of the body is zero since it is uniformly accelerated and initial velocity is 10m/s.
Know more :
1st equation of kinematics : v = u + at
2nd equation of kinematics : s = ut + 1/2at²
3rd equation of kinematics : v² = u² - 2as