Question

A uniformly accelerated car is found to process the velocities 12.5 m/s and 135 km/h two different places in its path if the car takes 10 minutes to travel between these places find the distance between them??​
a)25km
b)30km
c)5km
d)15km

Answer 1

Answer: 10.8 km

if 12.5 m/s is initial velocity (u) and 135km/h is final velocity (v)

Explanation

if 12.5 m/s is initial velocity (u) and 135 km/h is final velocity (v)

10 minutes = 10*60 s=600s

135 km/h= 135 *5/18=135/18/5 =27/18=9/6=3/2 => v= 1.5 m/s

using equation $v = u+at$

$a=v-u/t$

=> a=1.5-12.5/600 =-11/600 a= 11/600 m/s*s

$S=ut +0.5 at^{2}$

S=12.5* 600+ 0.5 11/600 *(600*600)

S=7500 +3300

S=10800 = 10.8 km

Answer 2

Answer:

• u=12.5m/s
• v=135km/h=135×5/18

=15×5/2=37.5m/s

• t=10min
• s=u+v/2×t

s=30/2×10

s=150