Physics, asked by anaswarakuf924, 6 months ago

A uniformly charged conducting sphere of 2.4 m diameter has a surface charge density of 80 μC/m 2 . calculate intensity of electric field due to sphere at the following points i) at the surface of the sphere ii)at the external point 0.8m from the surface of the sphere

Answers

Answered by khushiti
1

Answer:

(a)

d=2.4m

r=1.2m

Surface charge density, σ=80.0μC/m

2

=80×10

−6

C/m

2

Total charge on surface of sphere,

Q= Charge density × Surface area

=σ×4πr

2

=80×10

−6

×4×3.14×(1.2)

2

=1.447×10

−3

C

Therefore, the charge on the sphere is 1.447×10

−3

C.

(b)

ϕ

total

=

0

Q

0

=8.854×10

−12

N

−1

C

2

m

−2

Q=1.447×10

−3

C

ϕ

total

=

8.854×106−12

1.44×10

−3

=1.63×10

8

NC

−1

m

2

Therefore, the total electric flux leaving the surface of the sphere is 1.63×10

8

NC

−1

m

2

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