A uniformly charged conducting sphere of 2.4 m diameter has surface charge density of 80 C/m2
1) Calculate the electric field at a point on the surface of sphere
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Answer:
(a)
d=2.4m
r=1.2m
Surface charge density, σ=80.0μC/m
2
=80×10
−6
C/m
2
Total charge on surface of sphere,
Q= Charge density × Surface area
=σ×4πr
2
=80×10
−6
×4×3.14×(1.2)
2
=1.447×10
−3
C
Therefore, the charge on the sphere is 1.447×10
−3
C.
(b)
ϕ
total
=
∈
0
Q
∈
0
=8.854×10
−12
N
−1
C
2
m
−2
Q=1.447×10
−3
C
ϕ
total
=
8.854×106−12
1.44×10
−3
=1.63×10
8
NC
−1
m
2
Therefore, the total electric flux leaving the surface of the sphere is 1.63×10
8
NC
−1
m
2
Explanation:
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