= A uniformly tapering vessel shown in fig. 11.21, is filled with liquid of density 900 kg/m”. The force that acts on the base of the vessel due to liquid is (take g = 10 m/s?)
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Explanation:
As we know,
F=P × Area of base
F=(ρgh) × (Area of base)
F=900 (kg/m3)×10 (m/s2)×0.4 (m)×2×10−3 m2
∴F=7.2 N
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