Question

A unit cell consists of a cube in which anions (B) are present at each corner and cations (A) at the centre of the alternate faces of the unit cell. What is the simplest formula of the compound?

Answer 1

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Contribution of an atom placed at corner of the unit cell is 1/8

Therefore the total no. of anion (B) which are present in a unit cell is = 1/8 *total no. of corners= (1/8)* 8 =1  anion

Contribution of an atom placed at face centre  = 1/2

When cations are placed at the alternative faces the total no of face centred  atoms are 2.



therefore total no. of cations are = 1/2 * 2= 1

thus the formula of compound is  AB

Answer 2

✨✨ HEY DEAR HERE IS UR ANSWER❤❤✌✌

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➡ HERE, 8 atoms of Y r shared by the other 8 cells and those r :-

8×1 /8 = 1

✡✡ HERE IS :- X 

nd at the centre of the alternate faces r " FOUR "

➡ NOW we have,
4×1 / 2 = 2 ( as it is shared by the two cells)

✨✨ AND THE FORMULA OF THE COMPOUND IS " AB "

✔ So the answer is :- ( X2Y )

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