Question

.A unit cell of an element of atomic mass 108 m and density 10.5 g per cm³ has edge length 409 pm. find the structure of the crystal lattice?
plzz....

Answer 1

Answer:

We know that,

Density-

d=

a

3

×NA

Z×M

Given :

Molar Mass(M)=108g/mol

Density (d)=10.5g/cm

3

Edge Length(a)=409pm

Z=

M

d×a

3

×N

A

Value of N

A

is N

A

=6.023×10

23

Z=

108

10.5×(409×10

−10

cm

3

)

3

×6.023×10

23

=4

Number of atoms =4

Hence the element is packed in FCC structure.