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A unit cell of length of nacl crystal is 564 pm its density would be

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The unit cell length of sodium chloride crystal is 564 pm. What is its density?

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A)

Answer: 2.16×106gm−32.16×106gm−3

The density is given by the formula zMa3NAzMa3NA

Given a=564ppma=564ppm.

Each unit cell of NaCl has 4 Na−− and 4 Cl−− ions →z=4→z=4

Avagadro's number NA=6.022×1023/molNA=6.022×1023/mol

The total mass of NaCl =22.99+34.34=58.5g/mol=22.99+34.34=58.5g/mol

⇒⇒ Density ρ=zMa3NAρ=zMa3NA=4×58.5(564×10−12)36.022×1023=4×58.5(564×10−12)36.022×1023gm−3≈2.16×106gm−3gm−3≈2.16×106gm−3

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