Physics, asked by minnupeter, 6 months ago

A unit electric charge is kept at the point (0, 0, 2). The magnitude of the
electric field at the point (4, 4, 3) is
a) 1/9 units
b) 1/33 units
c) 1/87 units
d) Cannot be determined from the above​

Answers

Answered by HarineSakthivel
6

Explanation:

1/9 units is the right answer

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Answered by soniatiwari214
0

Concept:

  • The electric field of a unit charge
  • Vector calculations

Given:

  • Position of charge = (0, 0, 2)
  • Position of the point at which electric field is to be measured = (4, 4, 3)

Find:

  • The magnitude of the electric field at the point (4, 4, 3)

Solution:

The distance between the points (0, 0, 2) and (4, 4, 3) is

Vector R = (4i -0i) + (4j -0j) +(3z -2z)

Vector R = 4i + 4j +1z

The magnitude of R = √4²+4²+1² = √33

To determine the magnitude of the electric field, we need to know the value of the charge.

We do not have the value of the charge, so the magnitude of the electric field cannot be determined.

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