Question

A unit vector along the direction i+j+k has a
magnitude -​

Answer 1

Answer:

unit vector along (i + j) is (i + j)/√2

Step-by-step explanation:

unit vector along ( i + j) is ( i + j)/| i + j|

|i + j | is magnitude of ( i + j)

we know,

i and j are perpendicular to each other

So, |i + j| = √(i² + j² + 2.I.j.cos90°)

= √( 1 + 1) = √2

hence, unit vector along (i + j) is (i + j)/√2