A unit vector perpendicular to a =2i^+3j^+k^ and b =i^j^+k^ both is
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Answer:
Step-by-step explanation:
We know that cross product of any two vectors yields a vector which is perpendicular to both vectors
∴ for two vectors →Aand→B if →C is the vector perpendicular to both.
→C=→A×→B=⎡⎢⎣ˆiˆjˆkA1A2A3B1B2B3⎤⎥⎦
=(A2B3−B2A3)ˆi−(A1B3−B1A3)ˆj+(A1B2−B1A2)ˆk.
Inserting given vectors we obtain
→C=⎡⎢⎣ˆiˆjˆk2111−12⎤⎥⎦
=(1×2−(−1)×1)ˆi−(2×2−1×1)ˆj+(2×(−1)−1×1)ˆk.
=3ˆi−3ˆj−3ˆk.
Now unit vector in the direction of →C is →C∣∣∣→C∣∣∣
∴∣∣∣→C∣∣∣=√32+(−3)2+(−3)2
=√27
=3√3
Therefore desired unit vector is
1√3(ˆi−ˆj−ˆk)
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Answer:
Step-by-step explanation:
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