A uranium-238 nucleus,initially at rest emits an alpha particle with a speed of 1.4 m/s . Calculate the recoil speed of the residual nucleus thorium-234. Assume that the mass of nucleus is proportyional to the mass number.
Answers
Intially the momentu
m of mass no 238 i.e. uranium nucleus is zero as it at rest . After emission of the alpha particle the sum of momenta of alpha particle and remaining mass no 234 i.e. thorium is also zero ,because the radioactive emmision is purely internal process and no external force acts upon it . thus
multiplication of mass alpha and velocityalpha+ multiplication of massthorium and velocitythorium =0 (according to law of conservation of momentum) , so
velocity of thorium = -malpha particle / mthorium into velocityalpha
we know that massalpha / mass thorium = 4/234
given valpha = 1.17 into 107 so velocity of thorium = -4/234 into 1.17 into 107
= - 2 into 105 m/s here minus represents direction
Answer:
2.4 x 10^5
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