A urn contain 12 white and 8 red ball. Two balls are to be selected random and without replacement what is the probability that:
1. Both ball is white.
2. The first ball is white and the second ball is red.
3. One white ball and one red ball are selected
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Answer:
1)(12c2÷20c2)+(8c2÷20c2)
94/190
47/95
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