Question

(a) Using arrangement A, how many Rb atoms could be placed
on a square surface that is 1.0 cm on a side? (b) How many Rb
atoms could be placed on a square surface that is 1.0 cm on a
side, using arrangement B? (c) By what factor has the number
of atoms on the surface increased in going to arrangement B
from arrangement A? If extended to three dimensions, which
arrangement would lead to a greater density for Rb metal?

Answer 1

Answer:

B). How many Rb atoms could be placed on a square surface that is 1.0 cm on a side, using arrangement B? I was able to get A) answer = 4.1 x 1014 atoms/cm2, but I am really confused as to how to find out B)