Question

(a) Using Gauss’s law, derive expression for intensity of electric field at any point
near the infinitely long straight uniformly charged wire.

Answer 1

Explanation:

Electric field intensity at any point outside a uniformly charged spherical shell:

Consider a thin spherical shell of radius R and with centre O. Let charge + q be uniformly distributed over the surface of the shell.

Let P be any point on the Gaussian sphere S1 with centre O and radius r, as shown in the following figure.

According to Gauss's law, we can write the flux through ds as:

At any point on the surface of the shell, r = R

Field lines when charge density of the sphere is positive

Field lines when charge density of the sphere is negative

Hope it helps u.....