Question

(a)
Using Huygens's construction of secondary wavelets explain how a diffraction
pattern is obtained on a screen due to a narrow slit on which a monochromatic
beam of light is incident normally.​

Answer 1

Answer:

for the position of minimum intensity due to destructive interference we have

$asin\theta = n\lambda$

Explanation:

When light incident on the small slit then as per Huygen's principle we will say that wavefront of width same as the width of slit will move from it

Now we can say that each part of the slit will behave like a point source and it superimpose on the screen

Due to superposition of all the sources there is interference between them

Due to constructive interference we will get maximum on the screen and due to destructive interference we will get minimum intensity on the screen

So here we will have

$a sin\theta = n\lambda$

a = width of the slit

n = integer

so above is the equation to find the positions of destructive interference

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Topic : Diffraction

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