A Van is accelerated uniformly from 36 km per hour to 90 km per hour in 3 seconds calculate: the distance travelled by the Van in that time
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Given initial velocity(u) = 36km/hr = 36*5/18 = 10m/s
final velocity(v) = 90km/hr = 25m/s
time(t) = 3s
Acceleration(a) = (v-u)/t = (25-10)/3 = 5ms^-2
So distance covered = (v^2-u^2)/2a = (625-100)/10 = 525/10 m = 52.5 meters
So distance traveled is 52.5 meters in 3 sec.
final velocity(v) = 90km/hr = 25m/s
time(t) = 3s
Acceleration(a) = (v-u)/t = (25-10)/3 = 5ms^-2
So distance covered = (v^2-u^2)/2a = (625-100)/10 = 525/10 m = 52.5 meters
So distance traveled is 52.5 meters in 3 sec.
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