A van is moving with a speed of 72 kmph on a level road, where the coefficient of friction between tyres and road is 0.5. The minimum radius of curvature, the road must have, for safe driving of van, is (g=10m/s2)
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11
v = √μgr
r = v²/μg
r = 20(20)/0.5(10) 72kmph=20m/s
r = 400 m
Answered by
0
Answer:
80m
Explanation:
velocity=√ugr
r=v^2/ug
= 20*20/0.5*10=
**80***
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