Question

A varandah of width 2.25m is constructed all along outside a room which is 5.5cm long & 4m wide. Find the area of the varandah & the cost of cementing the floor of the varandah at the rate of 200/- per sqm

Answer 1

i) Area of verandah = Area of larger rectangle - Area of smaller rectangle

Finding length and breadth of both rectangles

Smaller rectangle

Length of smaller rectangle = 5.5 m

Breadth of smaller rectangle = 4 m

Larger Rectangle

Length of larger rectangle = Length of smaller rectangle + 2 × 2.25

= 5.5+2 (225 / 100)

= 5.5 (450/100)

= (55+45)/10

= 100/10

= 10m

: Breadth of larger rectangle = Breadth of smaller rectangle + 2 × 2.25

= 4 + 2 (225/100)

= 4 + 455/100

= (4 × 10 + 45)/10

= (40 + 45)/10

= 85/10

= 8.5 m

Larger rectangle

Length = l = 10 m

Breadth = b = 8.5m

Area of larger rectangle = l × b

= 10 x 8.5

= 85 m²

Smaller rectangle

Length = l = 5.5 m

Breadth= b = 4m

Area of smart rectangle = l × b

= 5.5 × 4

= 22 m²

Area of verandah = Area of larger rectangle - Area of smaller rectangle

= 85-22

= 63 m²

Area of path is 63 m²

ii) Cost of cementing verandah in 1 m² = Rs 200 Cost of cementing verandah in 63 m² = Rs 200 × 63

= Rs 12,600

It will cost Rs 12,600 for it's cementing.

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