Question

A variable force F=2x is applied what will be its workdone in moving a particle for X=10 to 0 a.-100J. b. -50J. c.+50J d.100J​

Answer 1

Answer:

Explanation:hey! mate here is your answer

Ans:- -100

∫ 2x =∫2 x^2/2

2×0-10^2/2

2×0-50

-100J

Answer 2

In these type of questions, follow the below process !

• Work done can be mathematically defined as :

$\boxed{ \displaystyle W = \int F \: dx}$

Putting limits:

$\implies \displaystyle W = \int_{10}^{0} F \: dx$

$\implies \displaystyle W = \int_{10}^{0} 2x \: dx$

$\implies \displaystyle W = \frac{2 {x}^{2} }{2} \bigg | _{10}^{0}$

$\implies \displaystyle W = {x}^{2} \bigg | _{10}^{0}$

$\implies \displaystyle W = {0}^{2} - {10}^{2}$

$\implies \displaystyle W = - 100 \: joule$

So, work done is -100 J (OPTION a).