Question

a varied inversely as b^3. if a=3/2 when b=2, find a when b is 3.

Answer 1

Given:

a ∝ 1/b³

If, b=2; then, a=3/2

To Find:

Value of 'a', if b=3

★Solution★

As, a ∝ 1/b³

» a=k/b³ ....(1)

[where, k is the constant of proportionality]

Given that, if b=2, then a=3/2

On substituting b and a as 2 and 3/2 respectively in (1), we get:

» 3/2=k/(2)³

or k=(2)³×(3/2)

» k=8×3/2

» k=4×3

∴ k=12

Now, for finding value of 'a' accordingly we must substitute b=3, and k=12, i.e.,

a=(12)/(3)³

a=12/27

∴ a=4/9

Answer 2

Answer:

hey there....!!!!

Step-by-step explanation:

as given : a = k/b³ , where k is constant.

when b = 2 , a = 3/2

put these values in equation to find value of k.

=> 3/2 = k/2³

=> 3/2 = k/8

=> k = 3×8/2 = 12

therefore the equation becomes : a = 12/b³

so when b = 3 then ,

=> a = 12/3³ = 12/27 = 4/9

=> a = 4/9 ans.

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Hope it will help u.

#Loafer