Question

A varies directly as the cube root of B when C is constant and varies inversely as the square root of C when B is constant. When a=5 b=125 and c=121 find A when B =64 and C=485​

Answer 1

Answer:

Step-by-step explanation:

According to question let, A=KC3B

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where K is a constant and A=3,B=256,C=2 satisfies the equation, So

3=K23256

​​=K816​=2K

K=23​

So

A=2C33B

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