Question

A varies directly as the sum of two quantities
B and 'C'. 'B' in turn varies directly as 'X' and 'c
varies inversely as 'x. When x = 1 or 2. A = 3. Find
the value of A when x = 4.​

Answer 1

Answer:

Step-by-step explanation:

A varies directly as sum of B and C

=> A= k(B+C) (k is some constant)

now, B varies directly as x

=> B=m1*x (m1 is some constant)

and C varies inversely as x

=> C=m2/x (m2 is some constant)

=>A=k(m1*x + m2/x)

=>A=px + q/x (p=k*m1 and q=k*m2 are replaced constants)

so, for x=2,

6= 2p + q/2

and for x=4,

9=4p + q/4

solving for p and q,

p=2

q=4

=>A=2x + 4/x

So, for x=16,

A=32.25