Math, asked by vanshikagurnani, 1 day ago

a varies inversely with the square of b. When bis 6, a is 96. Find a when bis 12.
24

Answers

Answered by spiderman2019
2

Answer:

Step-by-step explanation:

Since a varies inversely with the square of b,

a ∝ 1/b²

=> a = k/b² where k is a constant.

Now find value of k:

given, b = 6 and a = 96

=> 96 = k/6²

=> k = 36 * 96 = 3456.

So, the equation becomes a = 3456/b².

1) when b = 12

a = 3456/12² = 3456/144 = 24.

2) when b = 24,

a = 3456/24² = 3456/576 = 6.

Answered by Anonymous
0

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