Question

a vechile of mass 100 kg moving with velocity 10m/s . the force required to bring the rest in1/5 seconds will be​

Answer 1

Answer:

5000N

Explanation:

F=ma

a=velocity/time

a=10/1/5

a=50m/s^2

F=100*50

=5000N

Therefore,

Force required to bring vehicle to rest on 1/5 secs is 5000N

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Answer 2

Answer:

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