Question

A vector= 3i+4j+k and B vector= 2i +j-2k find B cap

Answer 1

Explanation:

B vector=2i+j-2k

B cap.|B|=B(vector)

Bcap=B(vector)/|B|

Since |B|= √(2)^2+(1)^2+(-2)^2

= √4+1+4 = √9 = 3

B cap= (2i+j-2k)/3

= (2/3)i+(1/3)j-(2/3)k