A vector=5i cap+ j cap + k cap vector B= -i cap + 5 j cap show that the vectors are perpendicular to each other
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The vectors will be perpendicular if the dot product of these two are zero.
Since A.B=ABcosθ
If θ=90 degrees, cosθ=0
A.B=0
So
A=5i+1j+1k
B=-1i+5j
A.B=((5)×(-1)+(1)×(5))
=(-5+5)
=0
Hence proved.
Since A.B=ABcosθ
If θ=90 degrees, cosθ=0
A.B=0
So
A=5i+1j+1k
B=-1i+5j
A.B=((5)×(-1)+(1)×(5))
=(-5+5)
=0
Hence proved.
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