A vector A has magnitude 2 and another vector B have magnitude 3 and is perpendicular to each other. By vector diagram find the magnitude of 2A B + and show its direction in the diagram.
CLASS - XI PHYSICS (Kinematics)
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26
|A| = 2
|B|= 3
let C = 2A
|C|=4
So |2A + B| = |C + B|
=√(C² + B² + 2CBcos90) (Ф= angle between A and B = 90°)
= √(16 + 9)
= + 5
Tan x = BsinФ/(C + BcosФ)
= 3/4
x = tan⁻¹(3/4) ≈ 37⁰
|B|= 3
let C = 2A
|C|=4
So |2A + B| = |C + B|
=√(C² + B² + 2CBcos90) (Ф= angle between A and B = 90°)
= √(16 + 9)
= + 5
Tan x = BsinФ/(C + BcosФ)
= 3/4
x = tan⁻¹(3/4) ≈ 37⁰
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